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Boyle's Law: Air trapped in a cylinder fitted with a piston occupies 136.5 mL at 1.05 atm pressure. What is the volume of air when the pressure is increased to 1.42 atm by applying force to the piston?

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Boyle's Law states that the pressure and volume of a gas are inversely proportional, as long as the temperature remains constant. This means that we can use the formula:

P1V1 = P2V2

where P1 and V1 are the pressure and volume at the initial state, and P2 and V2 are the pressure and volume at the final state.

We are given:

P1 = 1.05 atm
V1 = 136.5 mL
P2 = 1.42 atm

We can solve for V2:

P1V1 = P2V2

V2 = (P1V1) / P2

V2 = (1.05 atm x 136.5 mL) / 1.42 atm

V2 = 100.9 mL (rounded to one decimal place)

Therefore, the volume of air when the pressure is increased to 1.42 atm is about 100.9 mL.
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