Question

How many moles of sodium bromide can be produced from 1.03 moles sodium with o.650 moles bromine gas

Answer 1

1.03 moles of sodium and 0.650 moles of bromine gas will produce 0.650 moles of sodium bromide.

Step-by-step explanation:

To determine the number of moles of sodium bromide that can be produced, we need to consider the balanced equation for the reaction:

2Na + Br2 → 2NaBr

From the equation, we can see that 2 moles of sodium react with 1 mole of bromine gas to produce 2 moles of sodium bromide. Therefore, the ratio of moles of sodium to moles of sodium bromide is 2:2 = 1:1.

Given that we have 1.03 moles of sodium and 0.650 moles of bromine gas, we can conclude that we will produce 0.650 moles of sodium bromide.

Answer 2

To determine the number of moles of sodium bromide that can be produced, use the balanced equation and stoichiometric ratios. In this case, 1.03 moles of sodium and 0.650 moles of bromine gas will produce 2.33 moles of sodium bromide.

Step-by-step explanation:

To determine the number of moles of sodium bromide that can be produced, we need to use the balanced equation for the reaction:

2Na + Br₂ → 2NaBr

The stoichiometric ratio between sodium and sodium bromide is 2:2, meaning that for every 2 moles of sodium, 2 moles of sodium bromide are produced. Similarly, the stoichiometric ratio between bromine gas and sodium bromide is 1:2, meaning that for every 1 mole of bromine gas, 2 moles of sodium bromide are produced. Therefore, we can use these ratios to calculate the moles of sodium bromide produced:

• 1.03 moles of sodium × (2 moles of sodium bromide / 2 moles of sodium) = 1.03 moles of sodium bromide
• 0.650 moles of bromine gas × (2 moles of sodium bromide / 1 mole of bromine gas) = 1.30 moles of sodium bromide

Adding these two values together, we find that a total of 2.33 moles of sodium bromide can be produced from the given amounts of sodium and bromine gas.