Question

a fish tank has 150 gallons of water and is being drained at a rate of 1/2 gallon each second.A second fish tank has 120 gallons of water and is being filled at a rate of 1/4 gallons each second.After how many seconds will the two fish tanks have the same amount of water?

Answer 1

after 40 seconds, the two tanks will have the same amount of water.

Explanation:

Let x represent the number of seconds after which both tanks will have the same amount of water.

A fish tank has 150 gallons of water and is being drained at a rate of 1/2 gallons each second. It means that the number of gallons of water that would be in the tank after t seconds is 150 - 0.5t

A second fish tank has 120 gallons and it is being filled at a rate of 1/4 gallons each second. It means that the number of gallons of water that would be in the tank after t seconds is 120 + 0.25t

For the volume of both tanks to he the same, then

120 + 0.25t = 150 - 0.5t

0.25t + 0.5t = 150 - 120

0.75t = 30

t=40 seconds

Answer 2

120 seconds

Explanation:

To find the number of seconds it takes for the two fish tanks to have the same amount of water, we need to set up an equation to represent the amount of water in each tank at a given time.

Let's call the number of seconds it takes for the two tanks to have the same amount of water "t." At time "t," the amount of water in the first tank will be 150 - 0.5t, and the amount of water in the second tank will be 120 + 0.25t. We want to find the value of "t" that makes these two quantities equal.

So, we set up the equation 150 - 0.5t = 120 + 0.25t and solve for "t":

150 - 0.5t = 120 + 0.25t

0.25t = 30

t = 30 / 0.25

t = 120 seconds

Therefore, it will take 120 seconds for the two fish tanks to have the same amount of water.