First, let's calculate the number of moles of calcium hydroxide in the initial solution:
88.06 g Ca(OH)2 = 88.06/74.093 g/mol = 1.188 mol Ca(OH)2
To make 2.100 L of 0.250 M solution, we need:
2.100 L x 0.250 mol/L = 0.525 mol Ca(OH)2
Let's call the volume of the initial solution that we need to dilute "V":
V x (1.188 mol/1.520 L) = 0.525 mol/2.100 L
Solving for V, we get:
V = (0.525 mol/2.100 L) x (1.520 L/1.188 mol) = 0.336 L = 336 mL
The coefficient of this answer in scientific notation is 3.36 x 10^2.