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What is the molarity of a solution containing 5.035 grams of FeCIe in enough water to make 500 mL of solution?

User Yousuf
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To calculate the molarity of the solution, we first need to determine the number of moles of FeCl2 present in the solution.

The molar mass of FeCl2 is 126.75 g/mol (55.85 g/mol for Fe and 35.45 g/mol for Cl).

Number of moles of FeCl2 = mass of FeCl2 / molar mass of FeCl2
= 5.035 g / 126.75 g/mol
= 0.0397 mol

Now we can calculate the molarity of the solution:

Molarity = moles of solute / liters of solution

Since we have 500 mL of solution, we need to convert it to liters by dividing by 1000:

Liters of solution = 500 mL / 1000 mL/L
= 0.5 L

Now we can calculate the molarity:

Molarity = moles of solute / liters of solution
= 0.0397 mol / 0.5 L
= 0.0794 M

Therefore, the molarity of the solution containing 5.035 grams of FeCl2 in enough water to make 500 mL of solution is 0.0794 M.
User Kim Kling
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