Answer:
The period of a sine function of the form y = a sin bx is given by:
period = (2π) / |b|
In this case, the function is y = -1 sin 5x, which can be rewritten as y = -sin(5x). So, we can see that b = 5.
Substituting b = 5 into the formula, we get:
period = (2π) / |5|
period = π / 5
Therefore, the period of the function is π/5.