Question

PLEASE HELP!!!

What is the equation of a line, in point-slope form, that passes through (-2,-6) and has a slope of 1/3?
y-2=1/3(x-6)
y+2=1/3(x+6)
y-6=1/3(x-2)
y+6= 1/3(x+2)

Answer 1

Answer:y+6=1/3(x+2)

Explanation:

Hello!

You need to use the Point slope formula

y-y1=m(x-x1)

Plug your point into the equation with the slope (m)

y-(-6) =1/3(x-(-2))

Then simplify

y+6=1/3(x+2)