Answer:
1) 6 (the answer is 6)
Explanation:
First, let's calculate how much the textbooks cost in total: 30 textbooks * $116.00/textbook = $<<30*116=3480.00>>3480.00
Then, let's subtract the cost of the textbooks from the total amount of money the math department has available: $6500.00 - $3480.00 = $<<6500-3480=3015.00>>3015.00
Finally, we can divide the amount of money the math department has left by the cost of each laptop to determine how many laptops they can afford: $3015.00 / $439.00/laptop = 6.83 laptops
Since it's not possible to buy a fraction of a laptop, the math department can only buy 6 laptops. Therefore, the answer is 6, which corresponds to choice (1).