Question

You are helping with some repairs at home. You drop a hammer and it hits the floor at a speed of 4 feet per second. If the acceleration due to gravity (g) is 32 feet/second 2, how far above the ground (h) was the hammer when you dropped it? Use the formula:

Answer 1

Explanation:

vf = vo + at vo = 0 in this case ( you dropped it from 'at rest')

4 f/s = 32 t

t = 1/8 s

df = do + vot + 1/2 at^2 df = final position = 0 ft (on the ground)

0 = do + 0 + 1/2 (-32)(1/8)^2

solve for do = 1/4 foot