Answer:6a-25%
7a-50%
7b-50%
8. phenotypically normal male-X^HY,homozygous normal women-X^HX^H
probability of children with hemophilia-0%
Step-by-step explanation:
For 6- X^HX^h * X^HY
progeny- X^HX^H X^HY X^hX^H X^hY(25%)
for 7- X^HX^h * X^hY
progeny- X^HX^h(females without hemophilia) X^HY(males without hemophilia) X^hX^h(females with hemophilia-50% out of all female children) X^hY( male with hemophilia out of all male children-50%)