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Unit 8 homework 4 numbers 11 and 13

Unit 8 homework 4 numbers 11 and 13-example-1
User Anddy
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Explanation:

how could you solve 10., if you cannot solve 11. ? they are using the same thing : law of sine.

a/sin(A) = b/sin(B) = c/sin(C)

a, b, c being the sides, and A, B, C being the corresponding opposite angles.

11.

x/sin(90) = 13/sin(70)

as sin(90) = 1

x = 13/sin(70) = 13.83431104...

13.

remember, the sum of all angles in a triangle is always 180°.

angle JLM = 180 - 90 - 51 = 39°

angle LJK = 180 - 90 - 72 = 18°

14/sin(39) = JL/sin(51)

JL = 14×sin(51)/sin(39)

JL/sin(90) = JL = 14×sin(51)/sin(39) = KL/sin(18)

KL = 14×sin(51)×sin(18)/sin(39) = 5.342458907...

User Hkurabko
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