Question

A racing car consumes a mean of 87 gallons of gas per race with a standard deviation of 6 gallons.

if 41 racing cars are randomly selected, what is the probability that the sample mean would be greater than 88.1 gallons? Round your answer to four decimal places.

Answer 1

The probability is approximately 0.7734.

To find the probability that the sample mean would be greater than 88.1 gallons, we need to use the concept of the standard normal distribution.

First, we need to standardize the sample mean using the formula: Z = (X - μ) / (σ / √n), where X is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

In this case, X = 88.1, μ = 87, σ = 6, and n = 41.

Plugging in these values, we get Z = (88.1 - 87) / (6 / √41) = 0.752.

Next, we use a standard normal distribution table to find the probability corresponding to the Z value of 0.752.

From the table, the probability is approximately 0.7734.

Therefore, the probability that the sample mean would be greater than 88.1 gallons is 0.7734.

Answer 2

Answer: n=41

Explanation:

If 41 racing cars are randomly selected, what is the probability that the sample mean would be greater than 88.1 gallons? Round your answer to four decimal