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The point (8,15) lies on the terminal side of the angle 8. Find sin(0).

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Check the picture below.

let's find the hypotenuse


\textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=√(a^2 + o^2) \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{8}\\ o=\stackrel{opposite}{15}\\ \end{cases} \\\\\\ c=√(8^2+15^2)\implies \implies c=√(289)\implies c=17 ~\hfill \boxed{\sin( \theta )=\cfrac{\stackrel{opposite}{15}}{\underset{hypotenuse}{17}}}

The point (8,15) lies on the terminal side of the angle 8. Find sin(0).-example-1
User Deepak Sisodiya
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