Question

In exercises 10 and 11, points B and D are points off tangency. Find the value(s) of x.

2x^2+2x=7x+12

Answer 1

2x² + (2-7)x - 12 = 0

2x² - 5x - 12 = 0

x = 5 ± √(5² - 4 × 2 × (-12) ) /(2×2) = (5 ± √121)/4

x = (5+11)/4 = 4 and x = (5-11)/4 = - 3/2