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a package initially thrown horizontally at 40m/s at a height of 100m above the ground.Find the horizontal and vertical components of the velocity just before it hits the ground

User Sccs
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Answer:


V = < 40 m/s, -20√(5), 0 >

Step-by-step explanation:

To find the time it takes for the package to hit the ground:


yf = yi +Vi*t + 0.5*a*t^2\\0 = 100 + 0 +0.5*-10*t^2\\t = √(20)s

The horizontal component is 40 m/s before it hits the ground because there are no external forces acting on it.

To get the vertical velocity:


Vf = Vi + a*t\\Vf = 0 + -10*√(20) \\Vf = -20√(5)

User Ashton Honnecke
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