Register

Calculate %m/v composition of 0.022 Kg ammonium nitrate in 587g solution (d=1.07 g/mL)

Calculate %m/v composition of 0.022 Kg ammonium nitrate in 587g solution (d=1.07 g/mL)
153k views
1 vote
Calculate %m/v composition of 0.022 Kg ammonium nitrate in 587g solution (d=1.07 g/mL)

User Machinarius
by
8.1k points

1 Answer

6 votes


V_(tot) = (587 g)/(1,07 g/mL) = 549 mL

0,022 kg = 22 g


(m)/(V) = (22 g × 100)/(549 mL) = 4,0 %

User Alen Smith
by
8.7k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

Compare and contrast an electric generator and a battery??
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Link Copied!