Question

014 10.0 points

An engine using 1 mol of an ideal gas initially at 19.8 L and 424 K performs a cycle
consisting of four steps:
1) an isothermal expansion at 424 K from
19.8 L to 35.8 L ;
2) cooling at constant volume to 319 K ;
3) an isothermal compression to its original
volume of 19.8 L; and
4) heating at constant volume to its original
temperature of 424 K .
Find its efficiency. Assume that the
heat capacity is 21 J/K and the universal gas constant is 0.08206 L · atm/mol/K =
8.314 J/mol/K.

Answer 1

To find the efficiency of the engine, calculate the heat absorbed and heat rejected for each step of the cycle and substitute these values into the efficiency equation.

Step-by-step explanation:

The efficiency of an engine can be calculated using the equation:

Efficiency = 1 - (Qc/Qh)

Where Qc is the heat rejected and Qh is the heat absorbed.

In this case, we can calculate the heat absorbed and heat rejected for each step of the cycle and then substitute these values into the efficiency equation.