Question

Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1.

Answer 1

Answer: 0.6954

Explanation:

To find the area between two z scores, in this case P(-0.82<z<1.29), we can either use a z score calculator or a standard normal distribution table, which I will use for this.

The probability of P(-0.82<z<1.29) = P(z<1.29)-(z<-0.82).

To find P(z<2.01), we use a positive z score standard normal distribution table and find that P(z<1.29)=0.9015

Using a negative z score standard normal distribution table, we can find that (z<-0.82)=0.2061.

So, P(-0.82<z<1.29) = P(z<1.29)-(z<-0.82)=0.6954.