Question

Please help ASAP

How much energy is required to change a 35 g ice cube from ice at −12◦C to steam at 118◦C? The specific heat of ice is 2090 J/kg ·◦ C, the specific heat of water is 4186 J/kg ·◦ C, the specific heat of stream is 2010 J/kg ·◦ C, the heat of fusion is 3.33 × 105 J/kg, and the heat of vaporization is 2.26 × 106 J/kg.
Answer in units of J.

Answer 1

Step-by-step explanation:

First you have to warm up the ice to melting point ....melt it ....then heat the water to boiling point.....boil it to steam ...then heat the steam to 118 C

35 g = .035 kg

.035 kg ( 2090 J /( kg C) * (12C) + 3.33 x 10^5 J/kg + 4186 J/(kg C) * 100 C + 2.26 x 10^6 J/kg + 2010 J/(kg C) * 18 C ) =

107550.1 J round as appropriate