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Find the point that partitions segment AB in a 2:1 ratio when A(1,3)B(7,8)

Find the point that partitions segment AB in a 2:1 ratio when A(1,3)B(7,8)-example-1
User MePo
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1 Answer

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Answer:

X2 - X1 = 7 - 1 = 6

Y2 - Y1 = 8 - 3 = 5

L = (6^2 + 5^2)^1/2 = 7.81

2/3 L = 5.21 length of segment

Tan θ = 5 / 6 = .833 slope of line

θ = 39.8 deg

5.21 * sin 39.8 = 3.34

5.21 * cos = 39.8 = 4.00 gives length of line segments

x2 = 1 + 4 = 5

y2 = 3 + 3.34 = 6.34

(5, 6.34) = point 2/3 up the line

Check (length of line)

[(5 - 1)^2 + (6.34 - 3)^2]^1/2 =

l = 5.21 correct length for line segmet

User Sekomer
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