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What is the temperature of 0.59 mol of gas at a pressure of 1.0 atm and a volume of 11.0 L? (Express the temperature in kelvins to two significant figures).

1 Answer

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Answer:

T = 230 K

Step-by-step explanation:

Simply use the equation: PV = nRT, where P is pressure, V is volume, n is moles, R is 0.0821, and T is temperature in kelvin

Place the values in

(1.0 atm)(11.0 L)=(0.59 moles)(0.0821 Lxatm/Kxmol)(T)

Solve for T = 230 K

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