This is a binomial probability problem, where each human resource manager can be considered a Bernoulli trial with a success probability of 0.42 (i.e., the probability that they say job applicants should follow up within two weeks).
The probability of getting exactly k successes out of n trials is given by the binomial probability formula:
P(k) = (n choose k) * p^k * (1-p)^(n-k)
where (n choose k) is the number of ways to choose k successes out of n trials, p is the success probability, and (1-p) is the failure probability.
To find the probability of at least 2 successes out of 5 trials, we need to sum the probabilities of getting 2, 3, 4, or 5 successes:
P(at least 2) = P(2) + P(3) + P(4) + P(5)
P(2) = (5 choose 2) * 0.42^2 * 0.58^3 = 0.3249
P(3) = (5 choose 3) * 0.42^3 * 0.58^2 = 0.1645
P(4) = (5 choose 4) * 0.42^4 * 0.58^1 = 0.0419
P(5) = (5 choose 5) * 0.42^5 * 0.58^0 = 0.0053
P(at least 2) = 0.3249 + 0.1645 + 0.0419 + 0.0053 = 0.5366
Therefore, the probability that at least 2 out of 5 human resource managers say job applicants should follow up within two weeks is approximately 0.5366.