Question

Use the following calorimetric values to answer the question:

The specific heat capacity of water is 4,186 J/kg°C.

The specific heat capacity for copper is 387 J/kg°C.



A 120-g copper ball at 75 °C was dropped into 75 g of water. The final temperature of the water and the ball was 42 °C. What was the initial temperature of the water?

25 °C

37 °C

46 °C

51 °C

Answer 1

Step-by-step explanation:

Heat lost by copper ball = heat gained by water

(masses need to be in kg)

. 120 kg * 387 J /(kg C) * (75-42 C) = .075 kg * 4186 J/(kg C) * (42-x C)

.120 * 387 * 33 = .075* 4186* (42-x)

shows x = 37.1 C = initial water temp