Question

Below is a single die and a spinner with the numbers from 1 to 8.

(A) if the die is tossed and the pointer is spun what is the problability of getting a 5 on the die and a 7 on the spinner?


(B) What is the problability of getting a number less than 3 on the die and a number greater than 5 on the spinner?

Answer 1

(A) P(5 on die) = 1/6, P(7 on spinner) = 1/8

(1/6)(1/8) = 1/48

(B) P(less than 3 on die) = 2/6 = 1/3

P(greater than 5 on spinner) = 3/8

(1/3)(3/8) = 1/8