Answer:
Triangle NMO has vertices N(-4,-2), M(-1,-1), and O(-4,-5). To translate the triangle 7 units to the left, we subtract 7 from the x-coordinate of each vertex. This gives us:
N' = (-4 - 7, -2) = ( -11, -2)
M' = (-1 - 7, -1) = (-8, -1)
O' = (-4 - 7, -5) = (-11, -5)
So the image coordinates of N'M'O' are N'(-11, -2), M'(-8, -1), and O'(-11, -5). Therefore, the answer is D. N′(−11, −2), M′(−8, −1), O′ (−11, −5).