Question

How many moles of argon are there in a 22.4 L sample of gas at 101.3 kPa and

0°C?

Show your work

Answer 1

0.9994 moles of Ar

Step-by-step explanation:

Convert kPa to atm. 101.3 kPa is equal to approximately 1.0 atm.

Convert Temperature to kelvin K = 273 + C = 273 + 0 = 273K

R = 0.0821

Then use the gas law equation

PV = nRT, where p is pressure 1.0 atm, V is volume 22.4 L, and T is Temperature in Kelvin.

(1.0)(22.4)=n(0.0821)(273)

n = 0.9994 moles of Ar (Argon)