Answer:
a) The spectrum of the DSB-SC modulated signal s(t) can be obtained by multiplying the message signal M(f) with the carrier frequency c(t) as follows:
s(t) = M(f) * c(t) = tri(f/w) * 4 cos(2π fc t)
Using the trigonometric identity cos(A)cos(B) = 1/2 [cos(A+B)+cos(A-B)], we can write:
s(t) = 2tri(f/w)cos(2π fc t)cos(2π f t)
The spectrum of s(t) is therefore given by the product of the Fourier transforms of the triangular function and the cosine function:
S(f) = 2/2 [M(f-fc) + M(f+fc)] * 1/2 [δ(f-fc) + δ(f+fc)]
Simplifying, we get:
S(f) = tri((f-fc)/w) + tri((f+fc)/w)
b) The bandwidth of the DSB-SC modulated signal is twice the bandwidth of the message signal, i.e., 2 x 1500 = 3000 Hz. Therefore, the minimum carrier frequency to avoid sideband overlap is fc = 1500 Hz.
c) The spectrum of s(t) with fc = 5.5 kHz is shown below:
+-----------------------+
| |
| tri(f/w) |
| |
+------+-----------+-----------+-------+
-fc -1500 0 1500 3000 (Hz)
The important frequencies in the spectrum are:
Carrier frequency: fc = 5.5 kHz
Upper sideband frequency: fc + 1500 = 7.0 kHz
Lower sideband frequency: fc - 1500 = 4.0 kHz
d) A coherent demodulator can be used to recover the message signal without any amplitude gain or loss. The block diagram of the demodulator is shown below:
+--------------+
| |
| Local |
| Oscillator |
| cos(2π fct) |
| |
+-------+------+
|
|
v
+-------+------+
| |
| Product |
| Modulator |
| |
+-------+------+
|
|
v
+-------+------+
| |
| Low-pass |
| Filter |
| |
+--------------+
The received signal is multiplied with a local oscillator signal of the same frequency and phase as the carrier to obtain the product of the two signals. The resulting signal is then passed through a low-pass filter with cutoff frequency equal to the message bandwidth of 1500 Hz. The output of the filter is the demodulated message signal m(t).