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1 Answer

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First, we can write the quadratic function in the form:

ax^2 + bx + c = a(x^2 + (b/a)x) + c

ax^2 + bx + c = a(x^2 + (b/a)x + (b/2a)^2 - (b/2a)^2) + c

ax^2 + bx + c = a[(x + (b/2a))^2 - (b/2a)^2] + c

minimum value of this expression occurs when (x + (b/2a))^2 = 0, which is only possible when x = -(b/2a)

ax^2 + bx + c = a(0 - (b/2a)^2) + c = -b^2/4a + c

the minimum value of the quadratic function is -(Δ/4a), which is equivalent to -b^2/4a when a > 0

the function is zero when x = 1, so we can write:

a(1)^2 + b(1) + c = 0

a + b + c = 0

ax^2 + bx + c = a(x - h)^2 + k, where h = -b/2a and k = -b^2/4a + c

the value of the function at x = 0 is 5, so we have:

a(0)^2 + b(0) + c = 5

c = 5

k = -b^2/4a + c

k = -(-a-5)^2/4a + 5

Simplifying this expression, we get:

k = (-a^2 - 10a - 25)/4a + 5

k = (-a^2 - 10a + 15)/4a

Since we know that k = -4, we can write:

-4 = (-a^2 - 10a + 15)/4a

Multiplying both sides by 4a, we get:

-16a = -a^2 - 10a + 15

Simplifying this equation, we get:

a^2 - 6a - 15 = 0

Factoring this quadratic equation, we get:

(a - 5)(a + 3) = 0

So, either a = 5 or a = -3. If a = 5, we can solve for b using the equation a + b

*IG:whis.sama_ent

User Juagicre
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