Question

Find angle A to the nearest tenth.
(Show work if you can plss)

Answer 1

∠ A ≈ 36.9°

Explanation:

assuming the triangle to be right at ∠ C

using the sine ratio in the right triangle

sinA =
`(opposite)/(hypotenuse)` =
`(BC)/(AB)` =
`(6)/(10)` , then

∠ A =
`sin^(-1)` (
`(6)/(10)` ) ≈ 36.9° ( to the nearest tenth )