Question

A loop of area 0.100 m² is oriented at

a 15.5 degree angle to a 0.500 T
magnetic field. It rotates until it is at a
45.0 degree angle with the field. What
is the resulting CHANGE in the
magnetic flux?
[?] Wb

Answer 1

Flux = Area * Field

A1 = .1 m^3 * cos 64.5 since we need perpendicular area

A1 = .043 m^2 perpendicular to field

A2 = .1 m^3 * cos 45 = .071 m^2

A = (.071 - .043) m^2 = .028 m^2 change in area

Change in flux = .028 m^2 ^ .5 T = .014 T m^2