Question

PLS HELP!!!!!

Convert the following measurements. Show all work, including units that cancel.
82.6 L of neon at STP -> mol

Answer 1

Answer: To convert 82.6 L of neon at STP to moles, we need to use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

At STP, the pressure is 1 atm and the temperature is 273 K. The gas constant, R, is 0.0821 L·atm/(mol·K).

Therefore, we can rearrange the equation as:

n = PV/RT

n = (1 atm)(82.6 L)/(0.0821 L·atm/(mol·K))(273 K)

n = 3.43 mol

So, 82.6 L of neon at STP is equivalent to 3.43 mol of neon.

Answer 2

Step-by-step explanation:

To convert from liters of a gas at STP (standard temperature and pressure) to moles, we can use the conversion factor of 1 mole of a gas occupies a volume of 22.4 L at STP.

So, to convert 82.6 L of neon at STP to moles, we can use the following calculation:

82.6 L neon x (1 mol neon / 22.4 L neon) = 3.69 mol neon

Therefore, 82.6 L of neon at STP is equivalent to 3.69 mol of neon.