Answer:
100%
Explanation:
There are 8 equally probable outcomes on the spinner, numbered from 1 to 8. Of these, the even numbers are 2, 4, 6, and there are 6 numbers less than 7, namely 1, 2, 3, 4, 5, 6.
To find the probability of the pointer stopping on an even number or a number less than 7, we need to add the probabilities of these two events occurring and subtract the probability of both events occurring at the same time, since this would lead to double counting:
P(even or less than 7) = P(even) + P(less than 7) - P(even and less than 7)
P(even) = 3/8, since there are 3 even numbers on the spinner out of 8 total outcomes.
P(less than 7) = 6/8, since there are 6 numbers less than 7 on the spinner out of 8 total outcomes.
P(even and less than 7) = 1/8, since only 4 satisfies both conditions (even and less than 7) out of 8 total outcomes.
Therefore, substituting these values, we get:
P(even or less than 7) = 3/8 + 6/8 - 1/8
P(even or less than 7) = 8/8 = 1
So the probability that the pointer will stop on an even number or a number less than 7 is 1 or 100%.
Hope this helps!