Question

1. A type A man, whose father was type O, marries a woman whose mother was

heterozygous for type A and whose father was homozygous for type B.

Answer 1

Step-by-step explanation:

To solve this problem, we need to use Punnett squares to determine the possible blood types of their offspring.

Let's start by representing the alleles for blood type:

Type A: IAIA or IAi

Type B: IBIB or IBi

Type AB: IAIB

Type O: ii

The man is type A, which means he could be either IAIA or IAi. We don't know his genotype, so we'll represent it with "A." His father is type O, which means he must be ii.

The woman's mother is heterozygous for type A, which means she must be IAi. Her father is homozygous for type B, which means he must be IBIB.

We'll represent the woman's genotype as "AiBIB."

Now we can create a Punnett square as attached below.

The possible blood types of their offspring are:

AA: Type A

Ai: Type A

Bi: Type B

ABi: Type AB

So, the possible blood types of their offspring are Type A, Type B, and Type AB. There is no possibility of their offspring being Type O, since neither parent has the ii genotype needed to pass on the O allele.