Answer:
Without more information about the specific L. lactis groups being referred to, I cannot provide a definitive answer to this question. However, in general, the surface area-to-volume ratio of a cell can be calculated as follows:
Surface area-to-volume ratio = Surface area / Volume
The surface area of a cell is important because it determines the amount of nutrients and waste that can pass in and out of the cell. The volume of a cell is important because it determines the amount of metabolic activity that can occur within the cell.
In general, cells with a high surface area-to-volume ratio are more efficient at exchanging nutrients and waste, because they have a larger surface area relative to their volume. This is particularly important for cells that require a lot of nutrients to function, such as cells that are actively breaking down galactose.
If one of the L. lactis groups has a particularly high surface area-to-volume ratio, this could indicate that the cells in that group are particularly efficient at exchanging nutrients and waste, and thus may be more effective at breaking down galactose. However, other factors such as enzyme activity and gene expression could also play a role in determining how effectively the cells are able to break down galactose.