Question

What is the angular speed , in rad/s, of an object that completes 4.00 rev every 14.0 s?

Answer 1

The angular speed of an object that completes 4.00 revolutions every 14.0 seconds is approximately 0.899 rad/s.

Step-by-step explanation:

The angular speed of an object that completes 4.00 revolutions every 14.0 seconds can be calculated using the formula for angular velocity, which is ΔΘ divided by Δt. Since 1 revolution is 2π radians, we multiply 4 revolutions by 2π to get the total angle in radians, and then divide by the time, 14.0 seconds, to find the angular speed in rad/s.

The computation is as follows:

(4.00 rev) × (2π rad/rev) = 8π rad

8π rad ÷ 14.0 s = π rad/s ≈ 0.899 rad/s

Answer 2

The angular speed of the object that completes 4.00 revolutions every 14.0 seconds is 0.112 rad/s.

Step-by-step explanation:

The angular speed, also known as the angular velocity, is the change in angle per unit time. In this case, the object completes 4.00 revolutions every 14.0 seconds. One-fourth of a revolution is π/2 radians, and the time is 14.0 seconds. So, the angular speed can be calculated as follows:

Angular speed = Δθ / Δt = (π/2 rad) / (14.0 s) = 0.112 rad/s.

Therefore, the angular speed of the object is 0.112 rad/s.