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A stone of mass 2 kg rolls off the flat roof of a building reaches the ground with a speed of 10 m/s.

a.Calculate the kinetic energy of the stone when it reaches the ground
b the gravitational potential energy of the stone when it was on the roof
cthe height of the roof. Neglect air resistance.​

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Answer:

KE = 100J and PE = 100J

Step-by-step explanation:


KE = 0.5*m*v^2\\PE = m*g*h\\KE = 0.5*2*100 = 100 J

Potential energy at the start has to equal the kinetic energy at the end due to conservation of energy

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