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Find x,y if (x-1) 8i = 5 + (y² - 1) i​

User Mcheshier
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To solve for x and y, we can equate the real and imaginary parts of the equation.

Given: (x-1) 8i = 5 + (y² - 1) i

Real Part:
(x-1) 8 = 5
x-1 = 5/8
x = 5/8 + 1
x = 13/8

Imaginary Part:
(y² - 1) = 0
y² = 1
y = ±1

Therefore, the solutions are (x,y) = (13/8,1) and (13/8,-1).
User DWilches
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