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A compound contains 0.58 m Ag, 0.58 mol N, and 1.79 mol O. What is its empirical formula?

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Step-by-step explanation:

To find the empirical formula of the compound, we need to determine the simplest whole-number ratio of the atoms in the compound.

First, we need to find the number of moles of Ag, N, and O relative to each other. The smallest number of moles is used as a reference point, and the other moles are divided by this value to get their ratios:

0.58 mol Ag : 0.58 mol N : 1.79 mol O

Dividing each mole value by 0.58 mol (the smallest number of moles), we get:

1 mol Ag : 1 mol N : 3.09 mol O

We can see that the ratio of Ag:N:O is 1:1:3.09. However, we need to express the ratio in whole numbers, so we divide each number by the smallest number in the set of ratios:

1 : 1 : 3.09/1.00 ≈ 3.

Rounding to the nearest whole number, we get the empirical formula of the compound:

AgN3O3

Therefore, the empirical formula of the compound is AgN3O3.

User Vladimir Tolstikov
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