Question

When the state for a dispatcher object moves to signaled, the Windows kernel A) moves all threads waiting on that object to ready state if the dispatcher object is a mutex object B) moves a fixed number of threads (possibly greater than one) waiting on that object to ready state if the dispatcher object is a mutex object. C) moves all threads waiting on that object to ready state if the dispatcher object is an event object. D) moves a fixed number of threads (possibly greater than one) waiting on that object to ready state if the dispatcher object is an event object.

Answer 1

The option is C) moves all threads waiting on that object to a ready state if the dispatcher object is an event object.

When the state of a dispatcher object moves to signaled, the Windows kernel behaves differently depending on the type of object. If the object is a mutex, then all threads waiting on that object are moved to a ready state, regardless of the number of waiting threads.

This is because a mutex is a synchronization object that allows only one thread to access a shared resource at a time. Therefore, all waiting threads must be released to ensure that only one thread accesses the resource. On the other hand, if the dispatcher object is an event object, then the Windows kernel moves all waiting threads to a ready state.