Question

• read and understand hambley sections 5.1 through 5.4 • for v(t) = 160 cos (180πt 60) determine: • 1. vmax • 2. the phase angle θ. • 3. the angular frequency ω. • 4. vrms • 5. the phasor voltage v

Answer 1

Okay, let's go through this step-by-step:

1. vmax = 160 (the peak amplitude given in the voltage equation)

2. The voltage is varying cosinusoidally, so the phase angle θ = 0 degrees.

3. The angular frequency ω = (180*π)/60 = 3π radians/second

4. To find vrms (root mean square voltage), we calculate:

vrms = (vmax)/√2 = (160)/√2 = 113.39

5. The phasor voltage v = 160*e^j*0 = 160

So the answers are:

1. vmax = 160

2. θ = 0 degrees

3. ω = 3π radians/second

4. vrms = 113.39

5. v = 160

Let me know if you have any other questions!