Final answer:
The combustion of 2 mol of CH4 under standard conditions produces 1780.8 kJ of heat when the products are brought to 298 K and H2O is in the liquid state.
Step-by-step explanation:
To answer the question of how much heat is produced in the burning of 2 mol of CH4 under standard conditions while forming H2O(l), we refer to the balanced thermochemical equation for the combustion of methane: CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) + 890.4 kJ. This equation indicates that the combustion of 1 mol of CH4 produces 890.4 kJ of heat.
Using stoichiometry, we can determine the amount of heat produced by 2 mol of CH4. Since the reaction of 1 mol of methane releases 890.4 kJ, the reaction of 2 mol would release:
2 × 890.4 kJ = 1780.8 kJ
Therefore, the burning of 2 mol of CH4 under standard conditions produces 1780.8 kJ when products are brought to 298 K, and H2O is in the liquid state.