Answer:
1.58 g NaOH
Step-by-step explanation:
First we need to find the moles of Cd2+ ions.
Since we know the concentration which is .520 moles/L we can multiply this by the volume to get moles of Cd(NO3)2. We must also divide the volume by 1000 to get it into L from mL.
0.520 moles / L x (0.0380 L) = 0.0198 moles Cd(NO3)2. Since there is 1 mole of Cd for every mole of Cd(NO3)2 there is 0.0198 moles of Cd.
Precipitate formed will be Cd(OH)2 (s). For every mole formed it requires 2 moles of OH. Therefore the moles of OH must be 0.0198 x 2 = 0.0395 moles OH.
For every mole of OH there is 1 Mole of NaOH. Molar Mass of NaOH = 22.99 + 16.00 + 1.008 = 40.00 g/mol
Therefore multiply the moles of OH by the molar mass.
0.0395 moles x 40.00 g/mol = 1.58 g of NaOH