Question

What is the ph of a 0.001-m solution of hcl? (give the result in two sig fig)

Answer 1

Step-by-step explanation:

Simple use the equation pH = -log[H+].

Since HCl, hydrochloric acid is a strong acid it will dissociate completely.

This will result in 0.001 M = [H+] = [Cl-].

Then substitute into pH

pH = -log(0.001) = 3.0

(If you need to consider activity coefficients you will multiply the log function by the activity.)