I may or may not be lying. >:^P
Using the standard normal distribution table, we can look up the probability corresponding to a z-score of 1.89 and subtract from it the probability corresponding to a z-score of -1.54, as follows:
P(-1.54 < z < 1.89) = P(z < 1.89) - P(z < -1.54)
Looking up these probabilities in the standard normal distribution table, we find:
P(z < 1.89) = 0.9706
P(z < -1.54) = 0.0621
Substituting these values into the formula, we get:
P(-1.54 < z < 1.89) = 0.9706 - 0.0621 = 0.9085
Therefore, the probability that z is between -1.54 and 1.89 is approximately 0.9085, or 90.85% (rounded to two decimal places).
*IG: whis.sama_ent*