Final answer:
The lightning bolt delivers a charge of 2.25 C. For the minimum diameter of the lighting rod, we need additional information about the rod's material properties and the relationship between resistance and diameter, which is not provided in the question.
Step-by-step explanation:
Part A: Calculating Charge Delivered by a Lightning Bolt
To find the amount of charge delivered by a lightning bolt, we use the formula Q = I × t, where Q is the charge in coulombs (C), I is the current in amperes (A), and t is the time in seconds (s). In this case, the lightning bolt carries up to 45,000 A (45 kA) of current and lasts up to 50 microseconds (50 × 10⁻⁶ s). Therefore, the charge delivered by the lightning bolt is:
Q = 45,000 A × 50 × 10⁻⁶ s = 2.25 C
Part B: Calculating the Minimum Diameter of the Lightning Rod
To ensure that the potential difference between the top and bottom of the lightning rod does not exceed 130V, we must consider the rod's resistance and the current passing through it. The resistance (R) can be calculated using Ohm's law, R = V/I, where V is the voltage, and I is the current. However, without detailed information about the resistivity of the material or the formula for resistance in terms of diameter, we cannot provide an exact answer for the required diameter. We would need additional formulas and constants, such as the resistivity of iron and the formula for resistance based on the conductor's dimensions, to calculate the minimum diameter of the rod.