Question

Compound A has a molar mass of 20g/mol and compound B has a molar mass of 30g/mol.

1. How many moles of compound B are needed to have the same mass as 6.0 mol of compound A? (Please give explanation not only the answer)

Answer 1

9 moles

Step-by-step explanation:

To find out how many moles of compound B are needed to have the same mass as 6.0 mol of compound A, we need to use the molar mass of each compound and set up a proportion:

Moles of A / Molar mass of A = Moles of B / Molar mass of B

We know that the molar mass of compound A is 20 g/mol and that we have 6.0 mol of it, so:

6.0 mol A / 20 g/mol A = Moles of B / 30 g/mol B

Simplifying this equation:

0.3 mol A = Moles of B / 30

Multiplying both sides by 30:

9 mol B = 0.3 mol A

So, we need 9 moles of compound B to have the same mass as 6.0 mol of compound A.