Question

Two ohmic resistors (R, and R₂) are connected in series with a cell.

Find the resistance and power of R2, given that the current flowing
through R, and R₂ is 0.25A and that the voltage across the cell is 6 V, R₁ = 1 22.
R₂=?
R₁-19
V=6 V
I=0,25 A

Answer 1

23 ohm

Step-by-step explanation:

I = I1 = I2 = 0.25A

V = 6 V

V = V1 + V2

6 = I1R1 + I2R2

6 = ( 0.25 × 1 ) + ( 0.25 × R2 )

6 = 0.25 + 0.25 R2

6 - 0.25 = 0.25 R2

5.75 = 0.25 R2

5.75 ÷ 0.25 = R2

R2 = 23 ohm