Question

At the city museum, child admission is $5.60. and adult admission is $9.40. On wensday, 177 tickets were sold for a total of $1352.20. how many adult tickets were sold that day?​

Answer 1

Let's use variables to represent the number of child and adult tickets sold on Wednesday.

Let c be the number of child tickets sold, and let a be the number of adult tickets sold.

We know that the price of a child ticket is $5.60, and the price of an adult ticket is $9.40.

From the problem statement, we know that 177 tickets were sold in total, so:

c + a = 177

We also know that the total revenue from ticket sales was $1352.20, so:

5.60c + 9.40a = 1352.20

Now we have a system of two equations with two variables. We can solve for a by using the first equation to express c in terms of a, and then substituting into the second equation:

c + a = 177 --> c = 177 - a

5.60c + 9.40a = 1352.20

Substituting c = 177 - a into the second equation, we get:

5.60(177 - a) + 9.40a = 1352.20

Expanding and simplifying:

992.20 - 5.60a + 9.40a = 1352.20

3.80a = 360

a = 95

Therefore, 95 adult tickets were sold on Wednesday.

Answer 2

Its bugging out but I got 95 tickets I would add explanation if it didn't act out.

X=Adult tickets

Y=Child tickets

X+Y=117

Y=117-X

9.40X+5.60Y=1352.20

9.40X+5.60(117-X)=1352.20

9.40X+991.20-5.60x=1352.20

3.80X=361

X=95