Question

A heterozygous fire-breathing heterozygous winged dragon is crossed with one that cannot

breathe fire
and is heterozygous winged. How many of the offspring do not have wings and cannot breathe fire?

Answer 1

To solve this problem, we can use a Punnett square to determine the possible genotypes of the offspring.

First, let's assign the following letters to represent the alleles for fire-breathing and winged traits:

- F: allele for fire-breathing

- f: allele for not breathing fire

- W: allele for wings

- w: allele for no wings

The heterozygous fire-breathing dragon can be represented as Ff and the heterozygous winged dragon as Ww.

The Punnett square for this cross would look like:

```

| F f

---|-----

Ww | FW Ff

wW | fW ff

```

From this Punnett square, we can see that there are four possible genotypes for the offspring: FW, Ff, fW, and ff.

Out of these four possible genotypes, only one genotype (ff) would result in offspring that do not have wings and cannot breathe fire.

Therefore, the answer is: 1 out of 4 offspring will not have wings and cannot breathe fire.

Answer 2

One-fourth or 25% of the offspring will not have wings and cannot breathe fire.

The offspring of the cross between a heterozygous fire-breathing heterozygous winged dragon and one that cannot breathe fire and is heterozygous winged can have different combinations of traits. To determine how many of the offspring do not have wings and cannot breathe fire, we need to consider the possible combinations:

AABb (fire-breathing with wings)

AAbb (fire-breathing without wings)

aaBb (non fire-breathing with wings)

aabb (non fire-breathing without wings)

Out of these four possible combinations, only the aabb genotype represents offspring that do not have wings and cannot breathe fire. Therefore, one-fourth or 25% of the offspring will have this phenotype.