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Solve for x
x = 1+2+3+4..... Infinity

User Muhambi
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1 Answer

4 votes

Answer:

x = -1/12

Explanation:

It is actually a rather simple proof. Before we get to that, it’s important to understand a couple of other things. Let’s consider the following infinite summation:

X = 1 - 1 + 1 - 1 + 1 - 1 ...

Rearranging the above equation a little bit, we get:

X = 1 - (1 - 1 + 1 - 1 + 1 - 1 ...)

If you look at the term inside the brackets, it in fact equals X. So let’s substitute that:

X = 1 - X

2X = 1

X = 1/2

Now let’s consider another sum.

Y = 1 - 2 + 3 - 4 + 5 - ...

Writing it in another way, we get:

Y = 0 + 1 - 2 + 3 - 4 + 5 + ...

Adding the above two equations:

Y + Y = (1 - 2 + 3 - 4 + 5 ...) + (0 + 1 - 2 + 3 - 4 + 5 ...)

Grouping the corresponding terms within the brackets, we get:

2Y = 1 + 0 - 2 + 1 + 3 - 2 - 4 + 3 + 5 - 4 ...

2Y = 1 - (2-1) + (3-2) - (4-3) + ...

2Y = 1 - 1 + 1 - 1 + 1 - 1 ...

But the summation on the right hand side is X. Let’s substitute it:

2Y = X

2Y = 1/2

Y = 1/4

Finally, let’s consider our original question at hand i.e. the sum of all natural numbers:

S = 1 + 2 + 3 + 4 + ...

We defined Y earlier as:

Y = 1 - 2 + 3 - 4 + ...

Subtracting Y from S:

S - Y = 1 - 1 + 2 + 2 + 3 - 3 + 4 + 4 + ...

S - Y = 4 + 8 + 12 + 16 + ...

We just calculated the value of Y to be 1/4. So let’s substitute it:

S - 1/4 = 4 x (1 + 2 + 3 + 4 + ...)

S - 1/4 = 4S

3S = -1/4

S = -1/12

User Interkot
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